Q. A ball is released from the top of a tower. The ratio of work done by force of gravity in first, Second and third second of the motion of the ball is
A) 1:2:3
B) 1:4:9
C) 1:3:5
D) 1:5:3
Explanation
(c) When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third second
${\ \ \ \ h}_{I}:h_{II}:h_{III} = 1:2:3$[Because $h_{n} \propto (2_{n} - 1)\rbrack$
$\therefore Ratio\ of\ work\ done$
$mgh_{I}:mgh_{II}:mgh_{III} = 1:3:5\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.