Q. A particle is dropped from a height $h$. A constant horizontal velocity is given to the particle. Taking $g$ to be constant every where, kinetic energy $E$ of the particle $w.r.t.$ time $t$ is correctly shown in
A)
B)
C)
D)
Explanation
(a) As particle is projected with some velocity therefore its initial kinetic energy will not be zero
As it moves downward under gravity then its velocity increases with time $K.E. \propto v^{2} \propto t^{2}$ [As $v \propto t$]
So the graph between kinetic energy and time will be parabolic in nature
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.