Two springs have their force constants as $k_{1}$and $k_{2}\left( k_{1} k_{2} \right),$ when they are stretched by the same force

Question

Two springs have their force constants as $k_{1}$and $k_{2}\left( k_{1} > k_{2} \right),$ when they are stretched by the same force

Dr. Abubacker · Accepted Answer

(c) $w = \frac{F^{2}}{2k}$
If both springs are stretched by same force then $w \propto \frac{1}{k}.$
As${\ k}_{1} > k_{2}$therefore,$w_{1} < w_{2}$
I.e., more work is done in case of second spring.

Q. Two springs have their force constants as $k_{1}$and $k_{2}\left( k_{1} > k_{2} \right),$ when they are stretched by the same force

Explanation

Reviewed by Dr. Abubacker

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