Q. A quarter horse power motor runs at a speed of $600\ r.\ p.\ m.$ Assuming 40% efficiency the work done by the motor in one rotation will be

A) $7.46\ J$
B) $7400\ J$
C) $7.46\ ergs$
D) $74.6\ J$
Explanation

(a) Motor makes 600 revolution per minute
$\therefore n = 600\frac{revolution}{minute} = 10\frac{rev}{\sec}$
$\therefore$ Time required for one revolution $= \frac{1}{10}\ sec$
Energy required for one revolution = power$\ \times$ time
$= \frac{1}{4}\ \times 746 \times \frac{1}{10} = \frac{746}{40}\ J$
But work done $= 40\%$ of input
$= 40\% \times \frac{746}{40} = \frac{40}{100} \times \frac{746}{40} = 7.46\ J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.