(d) $E = \frac{p^{2}}{2m}\ \therefore m \propto \frac{1}{E}$ [If momentum are constant] $\frac{m_{1}}{m_{2}} = \frac{E_{2}}{E_{1}} = \frac{1}{4}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.