Two springs have force constants $k_{1}$ and $k_{2}$. There are extended through the same distance $x$. If their elastic energies are $E_{1}$ and $E_{2}$, then $\frac{E_{1}}{E_{2}}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(a) $E = \frac{1}{2}kx^{2}$
$	herefore\ \ E \propto k$
$	herefore\ \ \frac{E_{1}}{E_{2}} = \frac{k_{1}}{k_{2}}$

Q. Two springs have force constants $k_{1}$ and $k_{2}$. There are extended through the same distance $x$. If their elastic energies are $E_{1}$ and $E_{2}$, then $\frac{E_{1}}{E_{2}}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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