Q. If the kinetic energy of a body increases by $0.1\%$, the percent increase of its momentum will be
A) $0.05\ \%$
B) $0.1\ \%$
C) $1.0\ \%$
D) $10\ \%$
Explanation
(a) $P = \sqrt{2mE}\ \therefore P \propto \sqrt{E}$
Percentage increase in $P = \frac{1}{2}$ (percentage increase in $E$)
$= \frac{1}{2}(0.1\%) = 0.05\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.