Q. A man does a given amount of work in 10 s. Another man does the same amount of work in 20 s. The ratio of the output power of first man to the second man is
A) 1
B) $\frac{1}{2}$
C) $\frac{2}{1}$
D) None of these
Explanation
(c) Given ,$t_{1} = 10s,\ \ \ \ t_{2} = 20,\ \ \ \ \ w_{1} = w_{2}$
power$= \frac{work\ done}{time}$
or $\frac{p_{1}}{p_{2}} = \frac{w_{1}/t_{1}}{w_{2}/t_{2}}$
$\therefore\ \ \ \ \ \frac{p_{1}}{p_{2}} = \frac{t_{2}}{t_{1}} = \frac{2}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.