Q.
The force $F$ acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1$^{st}$ meter of the trajectory
A) $5\ J$
B) $10\ J$
C) $15\ J\ $
D) $2.5\ J$
Explanation
(d) Work done $(W) =$ Area under curve of $F$-$x$ graph
= Area of triangle $OAB = \frac{1}{2} \times 5 \times 1 = 2.5\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.