(c) $W = \mathrm{\Delta}K$ or $W_{T} + W_{g} + W_{F} = 0$
(Since, change in kinetic energy is zero)
[image:6_image70.emf]
Here, $W_{T} =$ work done by tension = 0
$W_{g} =$ work done by fore of gravity
$= - mgh$
$= - mgL(1 - \cos\theta)$
$\therefore\ \ W_{F} = - W_{g} = mgL(1 - \cos\theta)$