Q. An object of mass $m$ is tied to a string of length $L$ and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel $\theta$ with the vertical. Work done by the force $F$ is

A) $mgL(1 - \sin\theta)$
B) $mgL$
C) $mgL(1 - \cos\theta)$
D) $mgL(1 + \cos\theta)$
Explanation

(c) $W = \mathrm{\Delta}K$ or $W_{T} + W_{g} + W_{F} = 0$
(Since, change in kinetic energy is zero)
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Here, $W_{T} =$ work done by tension = 0
$W_{g} =$ work done by fore of gravity
$= - mgh$
$= - mgL(1 - \cos\theta)$
$\therefore\ \ W_{F} = - W_{g} = mgL(1 - \cos\theta)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.