A body of mass 6 kg is acted upon by a force which causes a displacement in it given by $x\frac{t^{2}}{4\ }\ \ $metre where t is the time in second. The work done by the force in 2s is

Question

Dr. Abubacker · Accepted Answer

(d) $m = 6kg,\chi = \frac{t^{2}}{4}$
$\frac{dx}{dt} = v = \frac{t}{2}$
$v(0) = 0\ and\ v(2) = \frac{2}{2} = 1$
${	herefore k}_{i} = \frac{1}{2}m(0)^{2}$
$and\ k_{f} = \frac{1}{2}m(1)^{2} = \frac{1}{2} = 	imes 6 	imes 1 = 3$
According to work-energy theorem
Work W$= K_{f} - k_{i} = 3 - 0 = 3J$

Q. A body of mass 6 kg is acted upon by a force which causes a displacement in it given by $x\frac{t^{2}}{4\ }\ \ $metre where t is the time in second. The work done by the force in 2s is

Explanation

Reviewed by Dr. Abubacker

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