Q. The area of the acceleration-displacement curve of a body gives
A) Impulse
B) Change in momentum per unit mass
C) Change in $KE$ per unit mass
D) Total change in energy
Explanation
(c) Area of acceleration–displacement curve gives change in $KE$ per unit mass
$\frac{1}{2}m\left( v^{2} - u^{2} \right) = F.S = \frac{mdv}{dt} \times s$
$\therefore\frac{change\ in\ KE}{Mass} = \frac{dv}{dt} \times s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.