A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $1g$ and $3g$. The total K.E. of the fragments is $6.4 imes 10^{4}\ J$. What is the K.E. of the smaller fragment

Question

A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $1g$ and $3g$. The total K.E. of the fragments is $6.4 	imes 10^{4}\ J$. What is the K.E. of the smaller fragment

Dr. Abubacker · Accepted Answer

(c) As the momentum of both fragments are equal therefore
$\frac{E_{1}}{E_{2}} = \frac{m_{2}}{m_{1}} = \frac{3}{1}$ $i.e$., $E_{1} = 3E_{2}$ …(i)
According to problem $E_{1} + E_{2} = 6.4 	imes 10^{4}\ J$ …(ii)
By solving equation (i) and (ii), we get
$E_{1} = 4.8 	imes 10^{4}\ J$ and $E_{2} = 1.6\  	imes 10^{4}\ J$

Q. A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $1g$ and $3g$. The total K.E. of the fragments is $6.4 \times 10^{4}\ J$. What is the K.E. of the smaller fragment

Explanation

Reviewed by Dr. Abubacker

Want more practice?