Two bodies of masses $m$ and $2m$ have same momentum. Their respective kinetic energies $E_{1}$ and $E_{2}$ are in the ratio

Question

Dr. Abubacker · Accepted Answer

(b) $E = \frac{P^{2}}{2m}$ If momentum are same then $E \propto \frac{1}{m}$
$	herefore\frac{E_{1}}{E_{2}} = \frac{m_{2}}{m_{1}} = \frac{2m}{m} = \frac{2}{1}$

Q. Two bodies of masses $m$ and $2m$ have same momentum. Their respective kinetic energies $E_{1}$ and $E_{2}$ are in the ratio

Explanation

Reviewed by Dr. Abubacker

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