(c) $P = \sqrt{2mE}\ \therefore P \propto \sqrt{m}$ (if $E =$ const) $\therefore\frac{P_{1}}{P_{2}\ } = \sqrt{\frac{m_{1}}{m_{2}}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.