A bucket full of water weighs 5 kg, it is pulled from a well 20 m deep. There is a small hole in the bucket through which water leaks at a constant rate of $0.2kgm^{- 1}$ .The total work done in pulling the bucket up from the well is ($g = 10ms^{- 2})$

Question

Dr. Abubacker · Accepted Answer

(a) The weight of bucket when it has been pulled up a distance $x\ is\ $(5-0.2$x).$
Hence, the required work is
$W = \int_{x = 20}^{x = 0}{- (5 - 0.2x) 	imes 10 	imes dx}$
$= \lbrack 50xbrack_{x = 0}^{x = 20} - \left\lbrack 2\frac{x^{2}}{2} ightbrack_{x = 0}^{x = 20}$
$W = 50 	imes 20 - ({20)}^{2} = 600$J

Q. A bucket full of water weighs 5 kg, it is pulled from a well 20 m deep. There is a small hole in the bucket through which water leaks at a constant rate of $0.2kgm^{- 1}$ .The total work done in pulling the bucket up from the well is ($g = 10ms^{- 2})$

Explanation

Reviewed by Dr. Abubacker

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