Q. The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is (take $g = 9.8\ ms^{- 2}$)
A) Zero
B) 980 J
C) 9800 J
D) 98 J
Explanation
(d) Slope of inclined plane, $\sin\theta = \ 1/100$
Component o weight down the inclined plane
$F = mg\sin\theta = 100 \times 9.8 \times 1/100 = 9.8\ N$
$s =$ distance moved = 10 m
$W = F\ s = 9.8 \times 10 = 98\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.