Q. Which of the following statements are incorrect? (i)If there were no friction, Work need to be done to move a body up an inclined plane is zero. (ii)If there were no friction, moving vehicles could not be stopped even by locking the brakes. (iii)As the angle of inclination is increased, the normal reaction on the body placed on it increases. (iv)A duster weighing 0.5 kg is pressed against a vertical board with a force of 11 N. If the coefficient of friction is 0.5, the work done in rubbing it upward through a distance of 10 cm is 0.55J.

A) (i)and(ii)
B) (i),(ii),(iv)
C) (i),(iii),and(iv)
D) All of these
Explanation

(c) The explanation are given below
(i)If a body is moved up in inclined plane, then the work done against friction force is zero as there is no friction. But a work has to be done against the gravity. So, this statement is incorrect.
(ii)If there were no friction, moving vehicles could not be stopped by locking the brakes. Vehicles are stopped by air friction only.
So , This Statement is correct.
(iii) In this situation the normal reaction is given by
[image:6_image76.jpeg]
$R = mg\cos\alpha\ \ \ \ \ \ \ldots\ldots.(i)$
If $\alpha$ increase then the value of cos $\alpha$ also decreases.
So, this Statement is incorrect.
(iv)When the duster is rubbing upward then an external force is applied and its value is
[image:6_image77.jpeg]
$F$’=0.5g+$\mu R$
$\therefore\ \ F^{''} = 0.5g + 0.5 \times 11$
Or $F^{''} = (0.5 \times 10 + 5.5)N$ (Here R=11 N)
Or $F^{''} = 10.5N$
Hence, work done in rubbing the duster through a distance of 10 cm.
$W = F^{''} \times d$
$\Rightarrow \ \ \ \ \ \ \ W = 10.5 \times \frac{10}{100}J$
Or $F^{''} = 10.5J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.