Q. If a lighter body (Mass $M_{1}$ and velocity $V_{1}$) and a heavier body (mass $M_{2}$ and velocity $V_{2}$) have the same kinetic energy, then
A) $M_{2}V_{2} < M_{1}V_{1}$
B) $M_{2}V_{2} = M_{1}V_{1}$
C) $M_{2}V_{1} = M_{1}V_{2}$
D) $M_{2}V_{2} > M_{1}V_{1}$
Explanation
(d) $P = \sqrt{2ME}$. If kinetic energy are equal then $P \propto \sqrt{m}$
$i.e$., heavier body posses large momentum
As $M_{1} < M_{2}$ therefore $M_{1}V_{1} < M_{2}V_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.