(d) $u = 10ms^{- 1},v = 20ms^{- 1}$ Work done = increase in kinetic energy $= \frac{1}{2} \times 500\left\lbrack 20^{2} - 10^{2} \right\rbrack = \frac{500 \times 30 \times 10}{2}$ $Power = \frac{500 \times 30 \times 10}{2 \times 60}W = 1250\ W$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.