Q. A block of mass $2\ kg$ is free to move along the $x$- axis. It is at rest and from $t = 0$ onwards it is subjected to a time-dependent force $F(t)$ in the $x$- direction. The force $F(t)$ varies with $t$ as shown in the figure. The kinetic energy of the block after $4.5$ seconds is

A) $4.50\ J$
B) $7.50\ J$
C) $5.06\ J$
D) $14.06\ J$
Explanation

(c) $\int_{}^{}{Fdt = \mathrm{\Delta}\rho}$
$\Rightarrow \frac{1}{2} \times 4 \times 3 - \frac{1}{2} \times 1.5 \times 2 = p_{f} - 0 \Rightarrow p_{f} = 6 - 1.5 = \frac{9}{2}$
$K.E. = \frac{p^{2}}{2m} = \frac{81}{4 \times 2 \times 2};K.E.\ = 5.06\ J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.