(c) $K_{1} = mgh_{1},\ K_{2} = mgh_{2}$ % Loss $= \frac{K_{1} - K_{2}}{K_{1}} \times 100$ $= \frac{h_{1} - h_{2}}{h_{1}} \times 100 = 50\%$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.