Q. A body of mass $0.1\ kg$ moving with a velocity of $10\ m/s$ hits a spring (fixed at the other end) of force constant $1000\ N/m$ and comes to rest after compressing the spring. The compression of the spring is
A) $0.01\ m$
B) $0.1\ m$
C) $0.2\ m$
D) $0.5\ m$
Explanation
(b) $\frac{1}{2}mv^{2} = \frac{1}{2}kx^{2} \Rightarrow x = v\sqrt{\frac{m}{k}} = 10\sqrt{\frac{0.1}{1000}} = 0.1\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.