Q. Two bodies of masses $2m$ and $m$ have their K.E. in the ratio $8:1$, then their ratio of momenta is
A) $1\ :1$
B) $2\ :1$
C) $4\ :1$
D) $8\ :1$
Explanation
(c) $p = \sqrt{2ME}\ \therefore\frac{p_{1}}{p_{2}} = \sqrt{\frac{m_{1}}{m_{2}}\frac{E_{1}}{E_{2}}} = \sqrt{\frac{2}{1} \times \frac{8}{1}} = \frac{4}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.