Q. A body falls on a surface of coefficient of restitution 0.6 from a height of $1\ m$. Then the body rebounds to a height of
A) $0.6\ m$
B) $0.4\ m$
C) $1\ m$
D) $0.36\ m$
Explanation
(d) $h_{n} = he^{2n} = 1 \times e^{2 \times 1} = 1 \times (0.6)^{2} = 0.36\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.