A shell of mass $20\ kg$ at rest explodes into two fragments whose masses are in the ratio $2\ :3$. The smaller fragment moves with a velocity of $6\ ms^{- 1}$. The kinetic energy of the larger fragment is

Question

Dr. Abubacker · Accepted Answer

(a) Mass of fragments are as 2 : 3
Total mass $= 20kg$
$	herefore$ Larger fragment $= 12kg$
$	herefore$ Smaller fragment $= 8\ kg$
Momentum is conserved
$	herefore 8 	imes 6 = 12 	imes v \Rightarrow v = 4 =$ velocity of larger fragment
$	herefore$ Kinetic energy $= \frac{1}{2}\ mv^{2} = \frac{1}{2} 	imes 12 	imes (4)^{2} = 96\ J$

Q. A shell of mass $20\ kg$ at rest explodes into two fragments whose masses are in the ratio $2\ :3$. The smaller fragment moves with a velocity of $6\ ms^{- 1}$. The kinetic energy of the larger fragment is

Explanation

Reviewed by Dr. Abubacker

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