(c) According to work-energy theorem,
$W = \mathrm{\Delta}K = 0$
$(\because Initial\ and\ final\ speeds\ are\ zero)$
$\therefore$ work done by friction +work done by gravity=0
$- \left( \mu\ mg\ \cos\varnothing \right)\ \frac{l}{2} + mgl\ \sin{\varnothing = 0}$
$or\ \ \frac{\mu}{2}\cos{\varnothing = \sin\varnothing}\ \ $
$\therefore\ \ \mu = 2\tan\varnothing$