(c) Given, velocity of river,(v)=2m/s
Density of water p=1.2 $gcc^{- 1}$
Mass of each cubic metre
$\ \ \ \ \ \ \ \ \ \ \ m = \frac{1.2 \times 10^{- 3}}{\left( 10^{- 2} \right)^{3}} = 1.2 \times 10^{3}\ kg$
$\therefore$ kinetic energy$= \frac{1}{2}mv^{2}$
$\ = \frac{1}{2} \times 1.2 \times 10^{3} \times (2)^{2}$
$= 2.4 \times 10^{3}\ J = 2.4\ KJ$