Q.
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20\ m$ is
A) $225\ J$
B) $200\ J$
C) $400\ J$
D) $175\ J$
Explanation
(b) [image:6_image88.emf]
Work done $W =$ area under $F - S$ graph
= area of trapezium $ABCD +$ area of trapezium $CEFD$
$= \frac{1}{2} \times (10 + 15) \times 10 + \frac{1}{2} \times (10 + 20) \times 5$
$= 125 + 75 = 200\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.