Q. A truck of mass $30,000\ kg$ moves up an inclined plane of slope 1 in 100 at a speed of $30\ kmph$. The power of the truck is (Given $g = 10\ ms^{- 2}$)
A) $25\ kW$
B) $10\ kW$
C) $5\ kW$
D) $2.5\ kW$
Explanation
(a) As truck is moving on an incline plane therefore only component of weight $(mg\sin\theta)$ will oppose the upward motion
Power $= force \times velocity = mg\sin\theta \times v$
$= 30000 \times 10 \times \left( \frac{1}{100} \right) \times \frac{30 \times 5}{18} = 25\ kW$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.