Q. A force of 5 N moves the particle through a distance of 10 m. If 25 J of work is performed, then the angle between the force and the direction of motion is
A) $0{^\circ}$
B) $90{^\circ}$
C) $30{^\circ}$
D) $60{^\circ}$
Explanation
(d) $s = 10m,F = 5$ N, $W = 25\ $J, $\theta = ?$
$\cos{\theta = \frac{W}{Fs}} = \frac{25}{5 \times 10} = \frac{1}{2}\ \ \ \ \ \therefore\theta = 60{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.