Q. The spring extends by $x$ on loading, then energy stored by the spring is : (If $T$ is the tension in spring and $k$ is spring constant)
A) $\frac{T^{2}}{2k}$
B) $\frac{T^{2}}{2k^{2}}$
C) $\frac{2k}{T^{2}}$
D) $\frac{2T^{2}}{k}$
Explanation
(a) $U = \frac{F^{2}}{2k} = \frac{T^{2}}{2k}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.