Q. From an automatic gun a man fires 360 bullet per minute with a speed of $360\ km/hour$. If each weighs $20\ g$, the power of the gun is
A) $600\ W$
B) $300\ W$
C) $150\ W$
D) $75\ W$
Explanation
(a) Power of gun $= \frac{Total\ K.E.\ of\ fired\ bullet}{time}$
$= \frac{n \times \frac{1}{2}mv^{2}}{t} = \frac{360}{60} \times \frac{1}{2} \times 2 \times 10^{- 2} \times (100)^{2} = 600\ W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.