Q. The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
A) 225J
B) 200J
C) 400J
D) 175J
Explanation
(b) Work done $W = Area\ ABCEFDA\ $
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = Area$ ABCD +Area CEFD
$= \frac{1}{2} \times (15 + 10) \times 10 + \frac{1}{2} \times (10 + 20) \times 5$
$= 125 + 75 = 200J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.