A uniform chain of length $L$ and mass $M$ is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If $g$ is acceleration due to gravity, the work required to pull the hanging part on to the table is

Question

Dr. Abubacker · Accepted Answer

(d) $W = \frac{MgL}{2n^{2}} = \frac{MgL}{2(3)^{2}} = \frac{MgL}{18}$ [ $n = 3$ Given ]

Q. A uniform chain of length $L$ and mass $M$ is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If $g$ is acceleration due to gravity, the work required to pull the hanging part on to the table is

Explanation

Reviewed by Dr. Abubacker

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