(b) Given $W = 25\ J,F = 5\ N,\mathrm{\Delta}s = 10m$
Work=Force$\times displacement$
$W = (F\cos\theta) \times \mathrm{\Delta}s$
Or $\cos\theta$=$\frac{W}{F \bullet \mathrm{\Delta}s}$
Or $\cos{\theta = \frac{25}{5 \times 10}} = \frac{1}{2}or\ \theta = \cos^{- 1}{\left( \frac{1}{2} \right) = 60{^\circ}}$
Hence, angle between force and direction of body is $60{^\circ}$.