A 5 kg brick of 20 cm $ imes$ 10 cm $ imes$ 8 cm dimensionless lying on the largest base. It is now made to stand with length vertical. If $g = 10ms^{- 2}$, then the amount of work done is

Question

A 5 kg brick of 20 cm $	imes$ 10 cm $	imes$ 8 cm dimensionless lying on the largest base. It is now made to stand with length vertical. If $g = 10ms^{- 2}$, then the amount of work done is

Dr. Abubacker · Accepted Answer

(a) Initial height of CG = 4 cm
Final height of CG =10 cm
Increase in height $= 6\ cm = 0.06\ m$
Work done $= \ 5 	imes 10 	imes 0.06 = 3\ J$

Q. A 5 kg brick of 20 cm $\times$ 10 cm $\times$ 8 cm dimensionless lying on the largest base. It is now made to stand with length vertical. If $g = 10ms^{- 2}$, then the amount of work done is

Explanation

Reviewed by Dr. Abubacker

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