A car of mass 1000 kg moves at a constant speed of $20\ ms^{- 1}$ up an incline. Assume that the frictional force is 200 N and that $\sin heta\ = \ 1/20$ where, $ heta$ is the angel of the incline to the horizontal. The $g = 10\ ms^{- 2}$. Find the power developed by the engine

Question

A car of mass 1000 kg moves at a constant speed of $20\ ms^{- 1}$ up an incline. Assume that the frictional force is 200 N and that $\sin	heta\ = \ 1/20$ where, $	heta$ is the angel of the incline to the horizontal. The $g = 10\ ms^{- 2}$. Find the power developed by the engine

Dr. Abubacker · Accepted Answer

(a) $P = (mg\sin	heta + F)v$
$= \left( 1000 	imes 10 	imes \frac{1}{20} + 200 ight) 	imes 20$
$= 1400\ W = 14\ kW$

Q. A car of mass 1000 kg moves at a constant speed of $20\ ms^{- 1}$ up an incline. Assume that the frictional force is 200 N and that $\sin\theta\ = \ 1/20$ where, $\theta$ is the angel of the incline to the horizontal. The $g = 10\ ms^{- 2}$. Find the power developed by the engine

Explanation

Reviewed by Dr. Abubacker

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