Q. What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of $10\ cm$ (Take $g = 9.8\ m/s^{2}$)
A) $0.6\ m/s$
B) $1.4\ m/s$
C) $1.8\ m/s$
D) $2.2\ m/s$
Explanation
(b) $v = \sqrt{2gh} = \sqrt{2 \times 9.8 \times 0.1} = \sqrt{1.96} = 1.4\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.