(c) $E = \frac{p^{2}}{2m}\ or\ E \propto p^{2}$ or $\frac{E_{1}}{E_{2}} = \left( \frac{p_{1}}{p_{2}} \right)^{2} = \left( \frac{p_{1}}{2p_{2}} \right)^{2} = \frac{1}{2}\ \ or\ \ E_{2} = 4E_{1}$ So, increase is 300%
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.