Q. In the non-relativistic regime, if the momentum, is increased by 100%, the percentage increase in kinetic energy is

A) 100
B) 200
C) 300
D) 400
Explanation

(c) $E = \frac{p^{2}}{2m}\ or\ E \propto p^{2}$
or $\frac{E_{1}}{E_{2}} = \left( \frac{p_{1}}{p_{2}} \right)^{2} = \left( \frac{p_{1}}{2p_{2}} \right)^{2} = \frac{1}{2}\ \ or\ \ E_{2} = 4E_{1}$
So, increase is 300%

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.