Q. The relationship between the force $F$ and position $x$ of a body is as shown in figure. The work done in displacing the body from $x = 1m$ to $x = 5m$ will be
A) $30\ J$
B) $15\ J$
C) $25\ J$
D) $20\ J$
Explanation
(b) Work done = area under $F$-$x$ graph
= area of rectangle $ABCD$ + area of rectangle $LCEF$ + area of rectangle $GFIH$ + area of triangle $IJK$
$= (2 - 1) \times (10 - 0) + (3 - 2)(5 - 0)$
$+ (4 - 3)( - 5 - 0) + \frac{1}{2}(5 - 4)(10 - 0) = 15\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.