A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $newton$ and $x$ in $metre$. The work done by the force in moving the object from $x = 0$ to $x = 6m$ is

Question

Dr. Abubacker · Accepted Answer

(b) Work done = Area enclosed by $F - x$ graph
$= \frac{1}{2}\  	imes (3 + 6) 	imes 3 = 13.5\ J$

Q. A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $newton$ and $x$ in $metre$. The work done by the force in moving the object from $x = 0$ to $x = 6m$ is

Explanation

Reviewed by Dr. Abubacker

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