Q.
A mass $m$ slips along the wall of a semispherical surface of radius $R$. The velocity at the bottom of the surface is
A) $\sqrt{Rg}$
B) $\sqrt{2Rg}$
C) $2\sqrt{\pi Rg}$
D) $\sqrt{\pi Rg}$
Explanation
(b) By applying law of conservation of energy
$mgR = \frac{1}{2}mv^{2} \Rightarrow v = \sqrt{2Rg}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.