A mass of $10\ g$ moving with a velocity of $100\ cm/s$ strikes a pendulum bob of mass $10\ g$. The two masses stick together. The maximum height reached by the system now is ($g = 10\ m/s^{2}$)

Question

Dr. Abubacker · Accepted Answer

(d) Initially mass $10\ gm$ moves with velocity $100\ cm/s$
$	herefore$ Initial momentum $= 10 	imes 100 = 1000\frac{gm 	imes cm}{\sec}$
After collision system moves with velocity $v_{sys}$. then
Final momentum $= (10 + 10) 	imes v_{sys.}$
By applying in conservation of momentum
$1000 = 20 	imes v_{sys.}$
$\Rightarrow v_{sys.} = 50\ cm/s$
If system rises upto height $h$ then
$h = \frac{v_{sys.}^{2}}{2g} = \frac{50 	imes 50}{2 	imes 1000} = \frac{2.5}{2} = 1.25\ cm$

Q. A mass of $10\ g$ moving with a velocity of $100\ cm/s$ strikes a pendulum bob of mass $10\ g$. The two masses stick together. The maximum height reached by the system now is ($g = 10\ m/s^{2}$)

Explanation

Reviewed by Dr. Abubacker

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