A particle is placed at the origin and force $F = kx$ is acting on it (where k is positive constant ).if $u(0) = 0.$the graph $u(x)$ versus x will (where u is potential energy function)

Question

Dr. Abubacker · Accepted Answer

(b) To leave the block, it oscillates in vertical plane. If maximum extension in spring in extreme position of block is $x_{1}$ , then
Work done by weight of the block
=Potential energy stored in spring
$mg\ x = \frac{1}{2}kx^{2}$
$	herefore x = 2\frac{mg}{k}\ 2d\ \ \ \ \ \ \ \ \ \ \ \ \ \ \left( \because d = \frac{mg}{k} ight)\ \ \ $

Q. A particle is placed at the origin and force $F = kx$ is acting on it (where k is positive constant ).if $u(0) = 0.$the graph $u(x)$ versus x will (where u is potential energy function)

Explanation

Reviewed by Dr. Abubacker

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