Q. Under the action of a force F=Cx, the position of a body changes from 0 to $x.$The work done is
A) $\frac{1}{2}Cx^{2}$
B) C$x^{2}$
C) C$x$
D) $\frac{1}{2}Cx$
Explanation
(a) Work done $W = \int_{0}^{x}{F.dx}$
$\ \ = \ \int_{0}^{x}{Cx\ dx = C\left( \frac{x^{2}}{2} \right)_{0}^{x}}$
$= \frac{1}{2}Cx^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.