(a) Given, m=2kg, v=20$ms^{- 1},$ $\theta = 60{^\circ}$
Power(P)is given as
$P = F \bullet v = Fv\cos\theta$
$P = mgv\ \cos\theta$
$\therefore\ \ P = 2 \times 20 \times 10 \times \cos{60{^\circ}}$
$P = 2 \times 20 \times 10 \times \frac{1}{2}$
$\Rightarrow \ \ \ \ P = 200\ W$