Q. The force constant of a wire is $k$ and that of another wire is $2k$. When both the wires are stretched through same distance, then the work done
A) $W_{2} = 2W_{1}^{2}$
B) $W_{2} = 2W_{1}$
C) $W_{2} = W_{1}$
D) $W_{2} = 0.5W_{1}$
Explanation
(b) $W = \frac{1}{2}kx^{2}$
If both wires are stretched through same distance then
$W \propto k$. As $k_{2} = 2k_{1}$ so $W_{2} = 2W_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.