Q. A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is
A) $1:2:3$
B) $1:4:9$
C) $1:3:5$
D) $1:5:3$
Explanation
(c) When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third second
$h_{I}:h_{II}:h_{III} = 1:3:5:$ [Because $h_{n} \propto (2n - 1)$]
$\therefore$ Ratio of work done $mgh_{I}:mgh_{II}:mgh_{III} = 1:3:5$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.