Q. A force of $5N$, making an angle $\theta$ with the horizontal, acting on an object displaces it by $0.4m$ along the horizontal direction. If the object gains kinetic energy of $1J$, the horizontal component of the force is
A) $1.5\ N$
B) $2.5\ N$
C) $3.5\ N$
D) $4.5\ N$
Explanation
(b) Work done on the body = K.E. gained by the body
$Fs\cos\theta = 1 \Rightarrow F\cos\theta = \frac{1}{s} = \frac{1}{0.4} = 2.5N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.